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4 votes
1. If x
y^(2) and xy are perfect squares, where x and y are positive integers, what is the smallest value of x + y?

User Ken Prince
by
8.4k points

1 Answer

3 votes

Answer:

8

Explanation:

xy^2 = k*k y^2 x = k * k so x has to be a perfect square.

xy is a perfect square which means that since x is a perfect square (see above) then y will have to be as well

There is nothing that prohibits x = 4 and y = 4 as being the answer where x = y.

I think the smallest possible value for x + y is 8.

This excludes any possibility of 1 or 0 in some combination, although I would look into 1.

User Sudarshan Kalebere
by
8.6k points

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