Question

After traveling steadily at 400 meters above a shipwrecked hull, a submerged vessel starts to descend when its ground distance

from the hull is 7 kilometers. What is the angle of depression for this part of the travel?
Select one
O a 1.00
6.327
C 86.73
d. 88.00

Answer 1

im trying to find this answer too dont worry :(

Explanation:

I dont know

Answer 2

Option B,
`3.27`

Explanation:

Given -

The submerged vessel travel horizontal distance above the shipwrecked hull

`= 400`

`= 0.4` kilometers

The vertical distance from the the shipwrecked hull to the ground is equal to
`7` kilometers

There forms a right angled triangle with

Base
`= 7` kilometer

Perpendicular
`=` 0.4 kilometer

Tan (angle)
`= (Perpendicular)/(Base)`

Substituting the given values we get -

Angle of depression

`= tan^(-1)((0.4)/(7))\\= 3.27`

Hence, option B is correct.