Question

A triangular field has sides of 120.32 m and 204.61 m, and the angle between them measures 60.881°. Find the area of the field

Answer 1

A=10753.5715 m^2.

Explanation:

The area of a triangle with the information SAS given is:

A=1/2 * (side) * (other side) * sin(angle between)

A=1/2 * (204.61)*(120.32) * sin(60.881)

A=10753.5715 m^2.

SAS means two sides with angle between.

Answer 2

Answer:
`10,753.57\ m^2`

Explanation:

You need to use the SAS area formula. This is:

`A=(a*b*sin(\alpha))/(2)`

You know that the triangular field has sides of 120.32 meters and 204.61 meters and the angle between them measures 60.881°. Then:

`a=120.32\ m\\b=204.61\ m\\\alpha =60.881\°`

Substituting these values into the formula, you get that the area of this triangle is:

`A=((120.32\ m)(204.61\ m)*sin(60.881\°))/(2)\\\\A=10,753.57\ m^2`