Answer: 3MeV electron
Step-by-step explanation:
m_e={9.1\times 10^{-31} m_α=4\times m_e m_a={9.1\times 10^{-31}
m_p=1.67\times 10^{-27}
(a) K.E. Energy of electron =
=3MeV
=1.05\times10^{18}

(b) K.E. Energy of alpha particle =
=10MeV
=0.88\times10^{18}

(c) K.E. Energy of auger particle =
=0.1MeV
=0.035\times10^{18}

(d) K.E. Energy of proton particle =
=400keV
=0.766\times10^{14}
/(s)](https://img.qammunity.org/2020/formulas/physics/college/r46yfkiotoif6pbruk1975yhcp384nx8o3.png)
from (a),(b),(c),and (d) we can clearly say that the velocity of the electron is more so the penetration of the electron will be deepest.