Question

What is the output of a system with the transfer function s/(s + 3)^2 and subject to a unit step input at time t = 0?

Answer 1

0

Step-by-step explanation:

output =transfer function H(s) ×input U(s)

here H(s)=
`(s)/((s+3)^2)`

U(s)=
`(1)/(s)` for unit step function

output =H(s)×U(s)

=
`(s)/((s+3)^2)`×
`(1)/(s)`

=
`(1)/((s+3)^2)`

taking inverse laplace of output

output=t×
`e^(-3t)`

at t=0 putting the value of t=0 in output

output =0