Answer:
C.
Explanation:
You are given 3x-4y<16 and we want to see which of the ordered pairs is a solution.
These ordered pairs are assumed to be in the form (x,y).
A. (0,-4) ?
3x-4y<16 with (x=0,y=-4)
3(0)-4(-4)<16
0+16<16
16<16 is not true so (0,-4) is not a solution of the given inequality.
B. (4,-1)?
3x-4y<16 with (x=4,y=-1)
3(4)-4(-1)<16
12+4<16
16<16 is not true so (4,-1) is not a solution of the given inequality.
C. (-3,-3)?
3x-4y<16 with (x=-3,y=-3)
3(-3)-4(-3)<16
-9+12<16
3<16 is true so (-3,-3) is a solution to the given inequality.
D. (2,-3)?
3x-4y<16 with (x=2,y=-3)
3(2)-4(-3)<16
6+12<16
18<16 is false so (2,-3) is not a solution to the given inequality.