Answer:
267
Explanation:
So we want to find the average of 4 numbers:
268, 258, 271, and x
The average of those 4 numbers is represented by the fraction:
![(268+258+271+x)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/59dgrwxihxgru4q61gvv57bcja6lbr4z0p.png)
Now we also wanting this average to be equal to 266. We need to find x such that that happens.
So we have the following equation to solve:
![(268+258+271+x)/(4)=266](https://img.qammunity.org/2020/formulas/mathematics/middle-school/an1t0d9a81vys7xut449w3tbjeq3aa5dgf.png)
Multiply both sides by 4:
![268+258+271+x=4(266)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3qo2k312gr4l4ybtj6nctdx84hzhz89jtj.png)
Do any simplifying on both sides:
![797+x=1064](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1nuufkyaoewf2a7wmdtjy6lg5as45biq5w.png)
Subtract 797 on both sides:
![x=1064-797](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pmonqazkfrskeyrra7xlbn3ebnrv1dkv1p.png)
Simplify:
![x=267](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mh9psymbka2gwmz1s3fpkg4dz2n3v5wptg.png)