Question

What is the energy of the photon that could cause (a) an electronic transition from then= 4 state to the n 5 state of hydrogen and (b) an electronic transition from the n 5 state to the n 6 state? What is the energy of the photon that could cause (a) an electronic transition from then= 4 state to the n 5 state of hydrogen and (b) an electronic transition from the n 5 state to the n 6 state?

Answer 1

a)
`E_photon =0.306 eV`

b)
`E_photon =0.166 eV`

Step-by-step explanation:

The energy of the photon (E) for
`n^th` orbit of the hydrogen atom is given as:

`E_photon = E_o((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))`

where,

`E_o` = 13.6 eV

n = orbit

a) Now for the transition from n = 4 to n = 5

`E_photon =13.6((1)/(4^(2))-(1)/(5^(2)))`

`E_photon =0.306 eV`

b) Now for the transition from n = 5 to n = 6

`E_photon =13.6((1)/(5^(2))-(1)/(6^(2)))`

`E_photon =0.166 eV`