Question

What is the de Broglie wavelength for a proton with energy 50 keV? Due to the limitations of Canvas, please give the wavelength in angstroms (x 10-10 m) to 2 sig figs.

Answer 1

1.2826 x 10^-13 m

Step-by-step explanation:

`\lambda  = (h)/(√(2 m K))`

Here, k be the kinetic energy and m be the mass

K = 50 KeV = 50 x 1.6 x 10^-16 J = 80 x 10^-16 J

m = 1.67 x 10^-27 kg

`\lambda  = \frac{6.63 *  10^(-34)}{\sqrt{2 * 1.67* 10^(-27)* 80* 10^(-16)}}`

λ = 1.2826 x 10^-13 m