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How do I solve this equation 4x^2-12x+29=20

User Shibu
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2 Answers

3 votes


4x^2-12x+29=20 \\4x^2-12x+9=0\\(2x-3)^2=0\\2x-3=0\\2x=3\\x=(3)/(2)

User Wellie
by
9.0k points
2 votes

With these kind of equations you want to use the quadratic formula. These problems take time, so don't fret you'll get there! :)

Quadratic formula:

-b +- √b^2-4(a)(c)

--------------------------

2(a)

Next find your a, b, and c!

a= 4

b=12

c=29

Time to plug those answers in.

12 +- √(-12)^2-4(4)(9)

-------------------------------

2(4)

Next solve everything in the radical first! Then the bottom.

12 +- √144-144

----------------------- ~ x=12/8 ~ x=3/2

8

You get: x=3/2!

User Ankush Raghuvanshi
by
8.4k points

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