Question

The temperature in a pressure cooker is 130 degree C while the water is boiling. Determine the pressure inside the cooker.

Answer 1

The pressure inside the cooker is 1.0804 atm.

Step-by-step explanation:

Boiling occurs when the vapor pressure becomes equal to atmospheric pressure.

For water, At standard conditions (Pressure = 1 atm) boiling occurs at 373.15 K.

So, Standard conditions:

T₁ = 373.15 K

P₁ = 1 atm

Given ,

The water boils at Temperature = 130 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So, the temperature, T₂ = (130 + 273.15) K = 403.15 K

To find pressure inside the cooker (P₂) :

Applying Amontons's Law as:

`\frac {P_1}{T_1}=\frac {P_2}{T_2}`

So,

`P_2=\frac {P_1}{T_1} * {T_2}`

`P_2=\frac {1 atm}{373.15 K} * {403.15 K}`

`P_2=1.0804 atm`

Thus, The pressure inside the cooker is 1.0804 atm.