Question

Need answer to A and B!

Answer 1

a)
`(14)/(285)`

b)
`(11)/(57)`

Explanation:

We are given that a committee of three people is selected at random from a set of eight teachers, seven parents of students, and five alumni.

We are to find:

a) the probability the committee consists of all teachers is:

Number of ways to select three that are all teachers =
`8C3`

Number of ways to select three randomly =
`20C3`

P (3 all teachers) =
`(8C3)/(20C3)` =
`(14)/(285)`

b) the probability the committee has no teachers is:

Number of ways to select three that it has no teachers =
`12C3`

Number of ways to select three randomly =
`20C3`

P (no teachers) =
`(12C3)/(20C3)` =
`(11)/(57)`