Question

Kinematics

A car starts from rest and reaches a speed of 80 ft/s after traveling 500 ft along a straight road.

Determine its constant acceleration and the time of travel.

Answer 1

The acceleration and time are 1.95 m/s and 12.5 s.

Step-by-step explanation:

Given that,

Speed = 80 ft/s =24.384 m/s

Distance = 500 ft =152.4 m

We need to calculate the acceleration

Using third equation of motion

`v^2-u^2= 2as`

`a = (v^2-u^2)/(2s)`

Where, u = initial velocity

v = final velocity

a = acceleration

s = distance

Put the value in the equation

`a=((24.384)^2-0)/(2*152.4)`

`a=1.95\ m/s^2`

We need to calculate the time

Using first equation of motion

`v=u+at`

`t =(v-u)/(a)`

`t=(24.384-0)/(1.95)`

`t =12.5\ s`

Hence, The acceleration and time are 1.95 m/s and 12.5 s.