J-s. If your 1400-kg car is parked in an 8.54-m-long garage, what is the uncertainty in its velocity? cm/s the tolerance is +/-2%

Question

asked Sep 10, 2020 62.2k views

1 Answer

Keshan De Silva · Answer 1 · 2020-09-16T03:35:08+0000

Answer:

$\Delta v = 4.41 * 10^(-37) cm/s$

Step-by-step explanation:

As per Heisenberg's uncertainty principle we know that

$\Delta P * \Delta x = (h)/(4\pi)$

so here we have

$\Delta P = m\Delta v$

$\Delta x = 8.54 m$

now from above equation we have

$m\Delta v * (8.54) = (h)/(4\pi)$

$1400(\Delta v) * (8.54) = (6.626 * 10^(-34))/(4\pi)$

$\Delta v = 4.41 * 10^(-39) m/s$

$\Delta v = 4.41 * 10^(-37) cm/s$