Question

ly charged particles are held 24 x 103m apart and then released from rest. The initial acceleration of the first particle is observed to be 7.0 m/s2 and that of the second to be 9.0 m/s2. The mass of the first particle is 6.3 x 107 kg. (a) What is the mass of the second particle? kg (b) What is the magnitude of the charge of each particle?

Answer 1

Part a)

`m_2 = 4.9 * 10^7 kg`

Part b)

`q_1 = q_2 = 5312.6 C`

Step-by-step explanation:

Part a)

As we know that both charge particles will exert equal and opposite force on each other

so here the force on both the charges will be equal in magnitude

so we will have

`F = m_1a_1 = m_2a_2`

here we have

`6.3 * 10^7(7) = m_2(9)`

now we have

`m_2 = 4.9 * 10^7 kg`

Part b)

Now for the force between two charges we can say

`F = (kq_1q_2)/(r^2)`

now we have

`(6.3 * 10^7)(7) = ((9* 10^9)q^2)/((24* 10^3)^2)`

now we have

`q_1 = q_2 = 5312.6 C`