Question

The probability of a basketball player making a free throw is 3/4. If the player attempts 11 free throws, what is the probability that exactly 5 are made?

Answer 1

0.0268.

Explanation:

This question can be solved using the binomial theorem.

Total attempts = n = 11

Required attempts = r = 5

Probability of success = p = 3/4 = 0.75

Binomial Theorem formula:

P(X=r) = nCr * p^r * (1-p)^(n-r).

Substituting the values:

P(X=5) = 11C5 * 0.75^5 * 0.25^6 = 0.0268 (to the nearest 3 significant figures).

So the probability that exactly 5 free throws are made out of 11 is 0.0268!!!