Question

If a point is positioned 16 inches from the origin on the x-y plane, and it is 12 inches above the x axis, what is its position in terms of the unit vectors i and j?

Answer 1

`p=12\hat{i}+10.58\hat{j}`

Step-by-step explanation:

distance of point from the origin is 16 inch

x-axis distance =12 inch

`p=\sqrt{x^2+y^2`

`y=√(p^2-x^2) \\y=√(16^2-12^2)\\ y=√(112)`

y=10.58 inch

`p=12\hat{i}+10.58\hat{j}`