Question

How many molecules of glucose are present in 1273 g. CaHlz0s?

Answer 1

Answer : The number of glucose molecule are,
`42.55* 10^(23)`

Explanation : Given,

Mass of
`C_6H_(12)O_6` = 1273 g

Molar mass of
`C_6H_(12)O_6` = 180.156 g/mole

First we have to calculate the moles of
`C_6H_(12)O_6`.

`\text{Moles of }C_6H_(12)O_6=\frac{\text{Mass of }C_6H_(12)O_6}{\text{Molar mass of }C_6H_(12)O_6}=(1273g)/(180.156g/mole)=7.066moles`

Now we have to calculate the number of molecules of glucose.

As, 1 mole of glucose contains
`6.022* 10^(23)` number of glucose molecules

So, 7.066 mole of glucose contains
`7.066* 6.022* 10^(23)=42.55* 10^(23)` number of glucose molecules

Hence, the number of glucose molecule are,
`42.55* 10^(23)`