Question

How much heat is needed to melt 13.74 kg of silver that is initially at 20°C?

Answer 1

`Q = 4.63 * 10^6 J`

Step-by-step explanation:

As we know that melting point of silver is

T = 961.8 degree C

Latent heat of fusion of silver is given as

L = 111 kJ/kg

specific heat capacity of silver is given as

`s = 240 J/kg C`

now we will have

`Q = ms\Delta T + mL`

`\Delta T = 961.8 - 20`

`\Delta T = 941.8 degree C`

now from above equation

`Q = (13.74)(240)(941.8) + (13.74)(111 * 10^3)`

`Q = 3.1 * 10^6 + 1.53 * 10^6`

`Q = 4.63 * 10^6 J`