Question

Given P(A) 0.169, P(B) 0.041, and P(C) 0.172, and that events A, B, and C are mutually exclusive, what is the P(A or B or C)? Answer in decimal form. Round to 3 decimal places as needed Your Answer: Answer

Answer 1

The value of P(A or B or C) is 0.382.

Explanation:

Given,

P(A) = 0.169,

P(B) = 0.041,

P(C) = 0.172

Since, if events A, B and C are mutually events ( in which no element is common ),

Then, P(A∪B∪C) = P(A) + P(B) + P(C)

Or P(A or B or C) = P(A) + P(B) + P(C),

By substituting the values,

P(A or B or C) = 0.169 + 0.041 + 0.172 = 0.382