Question

A wire carries a steady current of 2.60 A. A straight section of the wire is 0.750 m long and lies along the x axis within a uniform magnetic field, vector B = 1.50 k T. If the current is in the positive x direction, what is the magnetic force on the section of wire?

Answer 1

The magnetic force on the section of wire is
`-2.925\hat{j}\ N`.

Step-by-step explanation:

Given that,

Current
`I = 2.60\hat{i}\ A`

Length = 0.750 m

Magnetic field
`B = 1.50\hat{k}\ T`

We need to calculate the magnetic force on the section of wire

Using formula of magnetic force

`\vec{F}=l\vec{I}*\vec{B}`

`\vec{F}=0.750*2.60\hat{i}*1.50\hat{k}`

Since,
`\hat{i}*\hat{k}=-\hat{j}`

`\vec{F}=-2.925\hat{j}\ N`

Hence, The magnetic force on the section of wire is
`-2.925\hat{j}\ N`.