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Determine the force between two long parallel wires, that are separated by a dis- tance of 0.1m the wire on the left has a current of 10A and the one on the right BT has a current of 15A, both going up. 31十131

User Ntownsend
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1 Answer

5 votes

Answer:

3 x 10^-4 N/m

Attractive

Step-by-step explanation:

r = 0.1 m, i1 = 10 A, i2 = 15 A

The force per unit length between two parallel wires is given by


F = (\mu _(0))/(4\pi )* (2i_(1)i_(2))/(r)


F = (10^(-7)* 2* 10* 15)/(0.1)

F = 3 x 10^-4 N/m

Thus, the force per unit length between two wires is 3 x 10^-4 N/m, the force is attractive in nature because the direction of flow of current in both the wires is same.

User Uladzislau Vavilau
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9.5k points
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