Answer:
26.8 m/s
Step-by-step explanation:
= constant speed of the car
= speed of sound = 343 m/s
= actual frequency of the horn
= frequency heard as the car approach = 76 Hz
frequency heard as the car approach is given as

eq-1
= frequency heard as the car recedes = 65 Hz
frequency heard as the car goes away is given as

eq-2
dividing eq-1 by eq-2

= 26.8 m/s