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Calculate the pH of a 0.22 M ethylamine solution.
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3 votes
Calculate the pH of a 0.22 M ethylamine solution.

User Iheggie
by
5.7k points

2 Answers

4 votes

Answer:

pH = 10.1

Step-by-step explanation:

For weak base solutions [OH] = SqrRt([Base]·Kb

Then, from pH + pOH = 14 => pH = 14 - pOH

[OH} = SqrRt[(0.22)(5.6 x 10⁻⁴)] = 3.91

pH = 14 - 3.91 = 10.1

User Pavel Gurecki
by
6.7k points
5 votes

Answer:

answer is 12.18

Step-by-step explanation:

(C2H5NH2, Kb = 5.6 x 10-4.)

User Casa
by
5.6k points
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