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In triangle ABC a=2, c=3, B=95 degrees. Find the size of the smallest angle

User Trogper
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1 Answer

5 votes

Answer:

A ≈ 32°

Explanation:

You are given two sides and the angle between them, so the law of cosines applies. The measure of side b can be found to be ...

b² = a² + c² -2ac·cos(B)

b² = 2² +3² -2·2·3·cos(95°) ≈ 14.0459

b ≈ 3.74778

Then the law of sines can help you find angle A, the angle opposite the shortest side.

sin(A)/a = sin(B)/b

A = arcsin(a/b·sin(B)) = arcsin(2/3.74778·sin(95°)) ≈ 32.11°

A ≈ 32°

The smallest angle is about 32°.

User SParc
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