Question

An electromagnetic standing wave has a frequency of 120 MHz. (3396) Problem 2: What is the distance (in m) between adjacent antinodes of this standing wave?

Answer 1

The distance between adjacent antinodes of the standing wave is 1.25 m.

Step-by-step explanation:

Given that,

Frequency f= 120 MHz

We need to calculate the distance between adjacent antinodes of the standing wave

Using formula of distance

`\Delta x=(\lambda)/(2)`.....(I)

We know that,

`\lambda=(c)/(f)`

Put the value of
`\lambda` in to the equation (I)

`\Delta x=(c)/(2f)`

Where, c = speed of light

f = frequency

Put the all value into the formula

`\Delta x=(3*10^(8))/(2*120*10^(6))`

`\Delta x=1.25\ m`

Hence, The distance between adjacent antinodes of the standing wave is 1.25 m.