Question

At a point 1.2 m out from the hinge, 14.0 N force is exerted at an angle of 27 degrees to the moment arm in a plane which is perpendicular to the door. What is the magnitude of the torque?

Answer 1

`\tau = 7.63 Nm`

Step-by-step explanation:

As we know that moment of force is given as

`\tau = \vec r * \vec F`

now we have

`\vec r = 1.2 m`

`\vec F = 14 N`

now from above formula we have

`\tau = r F sin\theta`

here we know that

`\theta = 27 degree`

so we have

`\tau = (1.2)(14) sin27`

`\tau = 7.63 Nm`