Question

An FM radio consists of a series RLC circuit with a 6.57 pF (peco – 10-12) capacitor. If a person is dialed into a station broadcasting at 103.9 MHz, what is the inductance needed?

Answer 1

3.6 x 10⁻⁷ H

Step-by-step explanation:

C = capacitance of the capacitor = 6.57 x 10⁻¹² F

L = inductance of the inductor = ?

f = frequency of broadcasting system = 103.9 MHz = 103.9 x 10⁶ Hz

frequency is given as

`f = (1)/(2\pi √(LC))`

`103.6* 10^(6) = \frac{1}{2(3.14)\sqrt{(6.57* 10^(-12))L}}`

Inserting the values

L = 3.6 x 10⁻⁷ H