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1 vote
Factor each completely.

16) 5b^3 + 65b^2 + 60b

1 Answer

4 votes

Answer:


5b\left(b+1\right)\left(b+12\right)

Explanation:


5b^3+65b^2+60b\\\mathrm{Factor\:out\:common\:term\:}5b:\quad 5b\left(b^2+13b+12\right)\\=5b\left(b^2+13b+12\right)\\\mathrm{Factor}\:b^2+13b+12:\quad \left(b+1\right)\left(b+12\right)\\=5b\left(b+1\right)\left(b+12\right)

User Rick Ahlander
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