Answer:
![T_2 = 309 N](https://img.qammunity.org/2020/formulas/physics/college/t19v13l62gvjgvks9tqon8zs0sqyy7o0v5.png)
![T_1 = 489 N](https://img.qammunity.org/2020/formulas/physics/college/ag50m4tavh5spmrhsfu2a3dwp9200meeut.png)
Step-by-step explanation:
As we know that total tension in both the ropes is counter balancing the weight of scaffold and worker both
so here we will have
![T_1 + T_2 = (m + M)g](https://img.qammunity.org/2020/formulas/physics/college/39lmwcja37hcjzexqv9oqv6zn1el9rzec6.png)
now we have
![T_1 + T_2 = 198 + 600 = 798 N](https://img.qammunity.org/2020/formulas/physics/college/ngdua4fnd3q80e15eljkwzz6odfigsdafc.png)
now we also know that net torque due to both tension force in the string with respect to the position of worker must be zero so that platform will remain in equilibrium and horizontal in position
so here we will have
![T_1(1.12) + (198)(1.6 - 1.12) = T_2(3.2 - 1.12)](https://img.qammunity.org/2020/formulas/physics/college/2uqrweqftbpbfcsrrqsmnvpjd0ntnwuwj8.png)
![T_1+ 84.86 = 1.86 T_2](https://img.qammunity.org/2020/formulas/physics/college/mvm8sijtpdq5t15ux6wzv4nxlipf9p7lun.png)
now from above two equations we will have
![(1.86 T_2 - 84.86) + T_2 = 798](https://img.qammunity.org/2020/formulas/physics/college/ceouvltfo7075bidewik5rz51cbc5le48x.png)
![T_2 = 309 N](https://img.qammunity.org/2020/formulas/physics/college/t19v13l62gvjgvks9tqon8zs0sqyy7o0v5.png)
also we have
![T_1 = 489 N](https://img.qammunity.org/2020/formulas/physics/college/ag50m4tavh5spmrhsfu2a3dwp9200meeut.png)