Question

A wire with mass 60.0 g is stretched so that its ends are tied down at points 80.0 cm apart. The wire vibrates in its fundamental mode with frequency 65.0 Hz and with an amplitude of 0.500. What is the speed of propagation of transverse waves in the wire?

Answer 1

104 m/s

Step-by-step explanation:

L = length of the wire stretched between he two points = 80 cm = 0.80 m

f = fundamental frequency of vibration of the wire = 65.0 Hz

v = speed of propagation of transverse waves in the wire

Speed of propagation is given as

v = 2fL

inserting the values

v = 2 (65.0) (0.80)

v = (130) (0.80)

v = 104 m/s