Question

6x^2+2x=3 round to the nearest hundreths

Answer 1

x= 0.56, x= -0.89

`6x^2+2x=3\\Simplify =  6x^2+2x-3=0\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\quad x_(1,\:2)=(-b\pm √(b^2-4ac))/(2a)\\\mathrm{For\:}\quad a=6,\:b=2,\:c=-3:\quad x_(1,\:2)=(-2\pm √(2^2-4\cdot \:6\left(-3\right)))/(2\cdot \:6)\\x=(-2+√(2^2-4\cdot \:6\left(-3\right)))/(2\cdot \:6):\quad (-1+√(19))/(6)\\x=(-2-√(2^2-4\cdot \:6\left(-3\right)))/(2\cdot \:6):\quad -(1+√(19))/(6)\\`

`x=(-1+√(19))/(6),\:x=-(1+√(19))/(6)`