Answer:
Q = 378.247 Bt/hr
Step-by-step explanation:
given data:
diameter of container = 3 m
so r = 1.5 m
T1 = 50°C
T2 = 100°C
depth y = 3 ft
Heat transfer is given as Q

Where
S = Shape factor for the object


S = 25.132 ft

Q = 25.132*0.301 *(100-50)
Q = 378.247 Bt/hr