Answer:
2.07 m/s
Step-by-step explanation:
m = 1.07 x 10^5 kg, u1 = 3.41 m/s, u2 = 1.4 m/s
Let the speed of three coupled car after collision is v
Use conservation of momentum
m x u1 + 2 m x u2 = 3 m x v
u1 + 2 u2 = 3 v
3.41 + 2 x 1.4 = 3 v
v = 2.07 m/s