Question

A second's pendulum is taken to the moon. What will be the time period of the pendulum at the moon? (Acceleration due to gravity at the surface of the moon is 1/6 on the surface of earth).

Answer 1

4.89 seconds

Step-by-step explanation:

The time period of a pendulum is given by

`T = 2\pi \sqrt{(l)/(g)}`

For a second pendulum on earth, T = 2 second

`2 = 2\pi \sqrt{(l)/(g)}` ...... (1)

Now the time period is T when the pendulum is taken to moon and gravity at moon is 1/6 of gravity of earth

`T = 2\pi \sqrt{(l)/((g)/(6))}` ...... (2)

Divide equation (2) by equation (1)

`(T)/(2) = √(6)`

T = 4.89 seconds