Question

A spring with a mass of 0.7 kg is hanging on it and has an angular frequency of 2.4 when in oscillation. What is the spring constant? Calculate to one decimal place.

Answer 1

Spring constant, k = 2.304 N/m

Step-by-step explanation:

It is given that,

Mass of spring, m = 0.7 kg

Angular frequency,
`\omega=2.4\ rad/s`

We need to find the spring constant of the spring. It is a case of SHM. Its angular frequency is given by :

`\omega=\sqrt{(k)/(m)}`

`k=\omega^2* m`

`k=(2.4)^2* 0.4\ kg`

k = 2.304 N/m

So, the spring constant of the spring is 2.304 N/m. Hence, this is the required solution.