Question

A puck sliding on ice approaches a 20 degrees ramp at 10 m/s with coefficient of friction 0.2. How high will it go up the ramp along the ramp’s surface?

Answer 1

it will go up along the inclined plane by d = 9.62 m

Step-by-step explanation:

As we know that puck is moving upward along the slide

then the net force opposite to its speed is given as

`F_(net) = - mgsin\theta - \mu mgcos\theta`

so here deceleration is given as

`a = -g(sin\theta + \mu cos\theta)`

now plug in all values in it

`a = -9.81(sin20 + 0.2cos20)`

`a = -5.2 m/s^2`

now the distance covered by the puck along the plane is given as

`v_f^2 - v_i^2 = 2 a d`

`0 - 10^2 = 2(-5.2)d`

`d = 9.62 m`