Question

A flat circular coil having a diameter of 25 cm is to produce a magnetic field at its center of magnitude, 1.0 mT. If the coil has 100 turns how much current must pass through the coil?

Answer 1

The current pass through the coil is 6.25 A

Step-by-step explanation:

Given that,

Diameter = 25 cm

Magnetic field = 1.0 mT

Number of turns = 100

We need to calculate the current

Using the formula of magnetic field

`B =(\mu_(0)NI)/(2\pi r)`

`I=(B*2\pi r)/(\mu N)`

Where, N = number of turns

r = radius

I = current

Put the value into the formula

`I=(1.0*10^(-3)*2\pi*12.5*10^(-2))/(4\pi*10^(-7)100)`

`I=6.25\ A`

Hence, The current passes through the coil is 6.25 A