Question

A gear pump has a 4.25in outside diameter, a 3.25in inside diameter, and a 2in width. If the actual pump flow rate is 1800rpm and rated pressure is 29gpm, what is the volumetric efficiency?

Answer 1

volumetric efficeincy = 0.315%

Step-by-step explanation:

Given data:

outside diameter = 4.25 inch

inside diameter = 3.25 inch

flow rate V = 1800 rpm

actual flow rate Qa = 29gpm = 6699 inch3/min

volume of pump can be determine by using below formula

`VOLUME = (\pi)/(4)*(D_(0)^(2)-D_(1)^(2))L`

`=(\pi)/(4)*(4.25^(2)-3.25^(2))2`

`VOLUME = 11.78 inc^(3)`

theoretical flow rate is given as Qt

`Q_(T) = V.N`

= 11.78*1800

=
`21204 inch ^(3)/ min`

`volumetric efficeincy = (Q_(A))/(Q_(T))`

`=(6699)/(21204)`

volumetric efficeincy = 0.315%