Question

A 4.0 Ω resistor has a current of 3.0 A in it for 5.0 min. How many electrons pass 3. through the resistor during this time interval?

Answer 1

Number of electrons,
`n=5.62* 10^(21)`

Step-by-step explanation:

It is given that,

Resistance, R = 4 ohms

Current, I = 3 A

Time, t = 5 min = 300 s

We need to find the number of electrons pass through the resistor during this time interval. Let the number of electron is n.

i.e. q = n e ...............(1)

And current,
`I=(q)/(t)`

`I* t=n* e`

`n=(It)/(e)`

e is the charge of an electron

`n=(3\ A* 300\ s)/(1.6* 10^(-19))`

`n=5.62* 10^(21)`

So, the number of electrons pass through the resistor is
`5.62* 10^(21)`. Hence, this is the required solution.