Question

A car that was initially moving at 10 m/s is accelerated until its velocity reached 61 m/s. The change of the velocity took 6 s. What is the acceleration of the car in m/s^2? Please round your answer to two decimal places.

Answer 1

The acceleration of the car is 8.50 m/s²

Step-by-step explanation:

Given that,

Initial velocity = 10 m/s

Final velocity = 61 m/s

Time = 6 s

We need to calculate the acceleration of the car

Using equation of motion

`v=u+at`.....(I)

`a=(v-u)/(t)`

Where, u = initial velocity

v = final velocity

t = time

Put the value in the equation (I)

`a=(61-10)/(6)`

`a=8.50\ m/s^2`

Hence, The acceleration of the car is 8.50 m/s²