Question

A 30.6 kg mass attached to a spring oscillates with a period of 3.45 s. Find the force constant of the spring.

Answer 1

Force constant, K = 101.49 N/m

Step-by-step explanation:

It is given that,

Mass, m = 30.6 kg

Time period of oscillation, T = 3.45 s

We need to find the force constant of the spring. The time period of the spring is given by :

`T=2\pi\sqrt{(m)/(K)}`

`K=(4\pi^2m)/(T^2)`

`K=(4\pi^2* 30.6\ kg)/((3.45\ s)^2)`

K = 101.49 N/m

So, the force constant of the spring is 101.49 N/m. Hence, this is the required solution.