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A 4:1 scale drawing of a bearing is shown on an A-size print. Using a ruler, you measure the inside diameter of the part on the paper and you get 1.50 inches. What is the actual part size in inches? A. 6.0 B. 1.5 C.4.0 D 375

User MazeChaZer
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1 Answer

3 votes

Answer:

A. 6.0

Explanation:

We have been given that the the inside diameter of the part on the paper is 1.50 inches.

We have been given that scale is 4:1 for actual size to drawing side.


\text{Scale}=\frac{\text{Actual size}}{\text{Map size}}=(4)/(1)

Upon substituting 1.50 in our given proportion, we will get:


\frac{\text{Actual size}}{1.50\text{ inches}}=(4)/(1)


\frac{\text{Actual size}}{1.50\text{inches}}* 1.50\text{ inches}=(4)/(1)* 1.50\text{ inches}


\text{Actual size}=4* 1.50\text{ inches}


\text{Actual size}=6.0\text{ inches}

Therefore, the actual size is 6.0 inches and option A is the correct choice.

User Bokor
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