Question

A communication satellite is orbiting at an altitude of 3 earth radii above the ground. what is the speed?

Answer 1

4557.88 m/s

Step-by-step explanation:

M = mass of earth = 5.98 x 10²⁴ kg

R = radius of earth = 6.4 x 10⁶ m

r = orbital radius of satellite = 3R = 3 x 6.4 x 10⁶ = 19.2 x 10⁶ m

`v` = speed of the satellite

speed of the satellite is given as

`v=\sqrt{(GM)/(r)}`

`v=\sqrt{((6.67* 10^(-11))(5.98* 10^(24)))/(19.2* 10^(6))}`

`v` = 4557.88 m/s