Question

A 4.4 HP electric motor spins a shaft at 2329 rpm. Find: The torque load carried by the shaft is closest to: Select one: a)-27.06 ft*lb b. 19.24 ft*lb ? c)-31.17 ftlb d) 119.07 ftlb e)-9.92 ft*lb

Answer 1

Load carried by shaft=9.92 ft-lb

Step-by-step explanation:

Given: Power P=4.4 HP

P=3281.08 W

Power: Rate of change of work with respect to time is called power.

We know that P=
`Torque* speed`

`\omega=(2\pi N)/(60)` rad/sec

So that P=
`(2\pi NT)/(60)`

So 3281.08=
`(2\pi * 2329* T)/(60)`

T=13.45 N-m (1 N-m=0.737 ft-lb)

So T=9.92 ft-lb.

Load carried by shaft=9.92 ft-lb