Answer:
Speed of another player, v₂ = 1.47 m/s
Step-by-step explanation:
It is given that,
Mass of football player, m₁ = 88 kg
Speed of player, v₁ = 2 m/s
Mass of player of opposing team, m₂ = 120 kg
The players stick together and are at rest after the collision. It shows an example of inelastic collision. Using the conservation of linear momentum as :
![m_1v_1+m_2v_2=(m_1+m_2)V](https://img.qammunity.org/2020/formulas/physics/college/6w9mh38rh1k7qp6ufj5uoegu8ixd8awgqv.png)
V is the final velocity after collision. Here, V = 0 as both players comes to rest after collision.
![v_2=-(m_1v_1)/(m_2)](https://img.qammunity.org/2020/formulas/physics/college/mn0pc03c3heisuvgby3yu3b6nnfkabvv6s.png)
![v_2=-(88\ kg* 2\ m/s)/(120\ kg)](https://img.qammunity.org/2020/formulas/physics/college/br633ngk4t3r8vq8gfghplyb3pgrghk5u2.png)
![v_2=-1.47\ m/s](https://img.qammunity.org/2020/formulas/physics/college/ndm4f17zuep5wpye615lm5egiqoe9omvfa.png)
So, the speed of another player is 1.47 m/s. Hence, this is the required solution.