Question

A coil of 1000 turns of wire has a radius of 12 cm and carries a counterclockwise current of 15 A. If it is lying flat on the ground, and the Earth’s magnetic field points due north, has a magnitude of 5.8 x 10-5 T, and makes a downward angle of 25° with the vertical, what is the torque on the loop?

Answer 1

0.01663 Nm

Step-by-step explanation:

N = 1000, r = 12 cm = 0.12 m, i = 15 A, B = 5.8 x 10^-5 T, θ = 25

Torque = N i A B Sinθ

Torque = 1000 x 15 x 3.14 x 0.12 x 0.12 x 5.8 x 10^-5 x Sin 25

Torque = 0.01663 Nm