Question

A square loop of wire with initial side length 10 cm is placed in a magnetic field of strength 1 T. The field is parallel to the axis of the loop. Somebody carefully grabs the edges of the loop and begins pulling them apart such that the area of the loop increases at a rate of 20 cm2/s. What is the magnitude of the induced EMF in the loop?

Answer 1

2 x 10⁻³ volts

Step-by-step explanation:

B = magnetic of magnetic field parallel to the axis of loop = 1 T

`(dA)/(dt)` = rate of change of area of the loop = 20 cm²/s = 20 x 10⁻⁴ m²

θ = Angle of the magnetic field with the area vector = 0

E = emf induced in the loop

Induced emf is given as

E = B
`(dA)/(dt)`

E = (1) (20 x 10⁻⁴ )

E = 2 x 10⁻³ volts

E = 2 mV