Question

Ocean waves of wavelength 22 m are moving directly toward a concrete barrier wall at 4.0 m/s . The waves reflect from the wall, and the incoming and reflected waves overlap to make a lovely standing wave with an antinode at the wall. (Such waves are a common occurrence in certain places.) A kayaker is bobbing up and down with the water at the first antinode out from the wall. A) How far from the wall is she?B) What is the period of her up and down motion?

Answer 1

She is 22 m from the wall.

The period of her Bob is 5.5 sec.

Answer 2

If ocean waves of wavelength 22 m are moving directly toward a concrete barrier wall at 4.0 m/s .

A. The kayaker is 11 meters away from the wall.

B. The period of the kayaker's up and down motion is 5.5 seconds.

What is the distance?

A) The distance from the kayaker to the wall is:

Distance = 1/2 × Wavelength

Distance = 1/2 × 22 m

Distance = 11 m

Therefore the kayaker is 11 meters away from the wall.

B) The period can be calculated using the formula:

Period = 1 / Frequency

Use this formula:

Frequency = Velocity / Wavelength

Frequency = 4.0 m/s / 22 m

Frequency ≈ 0.182 Hz

Period:

Period = 1 / 0.182 Hz

Period ≈ 5.49 seconds

Period ≈ 5.5 seconds

Therefore, the period of the kayaker's up and down motion is approximately 5.5 seconds.