Question

When a boy pulls his sled with a rope, the rope makes an angle of 35° with the horizontal. If a pull of 16 pounds on the rope is needed to move the sled, what is the horizontal component force?

9 lb
13 lb
19 lb
22 lb

Answer 1

b.13 lb

Explanation:

We are given that a boy pulls his sled with a rope .

The rope makes an angle with horizontal =
`35^(\circ)`

If a pull on the rope is needed to move the sled=16 pounds

We have to find the horizontal component of force

We know that horizontal component force=
`fcos\alpha`

Therefore, we have f=16 pound

Then, horizontal component of force=
`16cos 35^(\circ)`

Horizontal component of force=
`16* 0.819=13.1lb`

Hence, horizontal component of force=13 lb

Answer:b.13 lb

Answer 2

13 lb

Explanation:

The horizontal component of the force is the magnitude of the force multiplied by the cosine of the angle with the horizontal.

(16 lb)·cos(35°) ≈ 13.1 lb ≈ 13 lb